A 6.00 kg mass is located at (2.00 m,2.00 m,2.00 m)and a 5.00 kg mass is located at (-1.0 m,3.00 m,-2.00 m).If this system of masses rotated about the X-axis perpendicular to the Z-Y plane,then the moment of inertia of this system is

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Quizplus · Accepted Answer

The moment of inertia about the X-axis is calculated using I = Σm*r^2, where r is the perpendicular distance from the axis. For the 6.00 kg mass, r = sqrt((2.00)^2 + (2.00)^2) = sqrt(8) m. For the 5.00 kg mass, r = sqrt((3.00)^2 + (-2.00)^2) = sqrt(13) m. Thus, I = 6*(sqrt(8))^2 + 5*(sqrt(13))^2 = 113 kg m^2.

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